SNAP Practice Test 2026

About the SNAP exam

The Symbiosis National Aptitude Test (SNAP) is a mba & business examination administered in India. It is designed to assess candidates' knowledge and proficiency across 4 key subject areas including General English, Quantitative Aptitude, Analytical & Logical Reasoning, Current Affairs. This exam is widely recognized as an essential benchmark for students and professionals.

Use short SNAP practice sets to identify topics to revisit. Choose a subject and difficulty, answer questions, then review the explanations. New accounts get 30 question credits; further new questions use paid credits. Retaking previously seen questions is free.

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SNAP — quick answers

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8 free SNAP practice questions (2026)

Answer these first — no signup, no card. Every answer is explained. For more practice, sign up for 30 free question credits and choose a subject above.

1. Find the remainder when 32^(32^32) is divided by 7.

   • 2
   • 4
   • 1
   • 6
   Show answer & explanation

   Answer: B. 4

   32 is congruent to 4 (mod 7). We need to find 4^(32^32) mod 7. By Euler's totient theorem, since gcd(4,7)=1, the cycle of exponents is phi(7) = 6. Now find 32^32 mod 6. 32 is congruent to 2 (mod 6). 2^32 mod 6 is always 4 because any even power of 2 greater than 1 is congruent to 4 (mod 6). Therefore, 4^(32^32) mod 7 = 4^4 mod 7 = 256 mod 7 = 4.

   Topic: Quantitative Aptitude · hard

2. Find the number of ordered pairs of positive integers (x, y) such that 1/x + 1/y = 1/(12!).

   • 10395
   • 5198
   • 12400
   • 9850
   Show answer & explanation

   Answer: A. 10395

   The equation is equivalent to (x - 12!)(y - 12!) = (12!)^2. The number of positive integral solutions is equal to the number of factors of (12!)^2. Prime factorization of 12! = 2^10 * 3^5 * 5^2 * 7^1 * 11^1. Thus, (12!)^2 = 2^20 * 3^10 * 5^4 * 7^2 * 11^2. The number of factors is (20+1)(10+1)(4+1)(2+1)(2+1) = 21 * 11 * 5 * 3 * 3 = 10395.

   Topic: Quantitative Aptitude · hard

3. If log_x(2) * log_(x/16)(2) = log_(x/64)(2), find the sum of all possible real values of x.

   • 12
   • 10
   • 16
   • 14
   Show answer & explanation

   Answer: A. 12

   Let y = log_2(x). Then log_x(2) = 1/y, log_(x/16)(2) = 1/(y - 4), and log_(x/64)(2) = 1/(y - 6). The equation becomes (1/y) * (1/(y - 4)) = 1/(y - 6). Solving this gives y^2 - 4y = y - 6, which simplifies to y^2 - 5y + 6 = 0. Thus, y = 2 or y = 3. This yields x = 2^2 = 4 or x = 2^3 = 8. The sum of possible values of x is 4 + 8 = 12.

   Topic: Quantitative Aptitude · hard

4. Find the range of the function f(x) = (x^2 - 3x + 4)/(x^2 + 3x + 4) for all real values of x.

   • [1/7, 7]
   • [1/5, 5]
   • [-7, 7]
   • (0, 7]
   Show answer & explanation

   Answer: A. [1/7, 7]

   Let y = (x^2 - 3x + 4)/(x^2 + 3x + 4). Rearranging, we get (y - 1)x^2 + 3(y + 1)x + 4(y - 1) = 0. Since x is real, the discriminant of this quadratic equation in x must be greater than or equal to 0: D = [3(y+1)]^2 - 4(y-1)[4(y-1)] >= 0. Simplifying this gives 9(y^2 + 2y + 1) - 16(y^2 - 2y + 1) >= 0, which reduces to 7y^2 - 50y + 7 <= 0. Solving this quadratic inequality yields 1/7 <= y <= 7.

   Topic: Quantitative Aptitude · hard

5. If the roots of the equation x^3 - 12x^2 + 39x - k = 0 are in arithmetic progression, find the value of k.

   • 24
   • 28
   • 32
   • 36
   Show answer & explanation

   Answer: B. 28

   Let the roots be a - d, a, and a + d. The sum of the roots is 3a = 12, which gives a = 4. Since a = 4 is a root of the equation, substituting x = 4 must satisfy it: 4^3 - 12(4^2) + 39(4) - k = 0 => 64 - 192 + 156 - k = 0 => 28 - k = 0 => k = 28.

   Topic: Quantitative Aptitude · hard

6. Three runners A, B, and C run around a circular track of length 12 km starting from the same point at the same time in the same direction. Their speeds are 3 km/h, 7 km/h, and 13 km/h respectively. After how much time will they meet together for the first time anywhere on the track?

   • 12 hours
   • 6 hours
   • 3 hours
   • 4 hours
   Show answer & explanation

   Answer: B. 6 hours

   Let t be the time when they meet. The relative distances run must be integer multiples of the track length. Thus, t(v_B - v_A) = 12*k_1 and t(v_C - v_A) = 12*k_2 for integers k_1, k_2. This gives 4t = 12*k_1 => t = 3*k_1 and 10t = 12*k_2 => t = 1.2*k_2. Equating both, 3*k_1 = 1.2*k_2 => 5*k_1 = 2*k_2. The smallest positive integers satisfying this are k_1 = 2 and k_2 = 5, which gives t = 6 hours.

   Topic: Quantitative Aptitude · hard

7. A person can walk up a moving up-escalator in 40 seconds. The same person can run up the same moving up-escalator in 24 seconds by doubling his walking speed. How many seconds would it take for the person to just stand on the escalator and go up?

   • 80 seconds
   • 120 seconds
   • 100 seconds
   • 60 seconds
   Show answer & explanation

   Answer: B. 120 seconds

   Let v_w be the walking speed, v_e be the escalator speed, and D be the distance. D/(v_w + v_e) = 40 and D/(2v_w + v_e) = 24. Thus, 40(v_w + v_e) = 24(2v_w + v_e) => 40v_w + 40v_e = 48v_w + 24v_e => 16v_e = 8v_w => v_w = 2v_e. Substitute v_w back: D = 40(2v_e + v_e) = 120v_e. The time to stand and go up is D/v_e = 120 seconds.

   Topic: Quantitative Aptitude · hard

8. A, B, and C can do a piece of work in 24, 32, and 48 days respectively. They start together. A leaves after 5 days. B leaves 3 days before the completion of the work. In how many days is the work finished?

   • 15 days
   • 17 days
   • 19 days
   • 21 days
   Show answer & explanation

   Answer: B. 17 days

   Let total work be LCM(24, 32, 48) = 96 units. Rates: A = 4 units/day, B = 3 units/day, C = 2 units/day. Let total days be d. A works for 5 days (5 * 4 = 20 units). B works for (d - 3) days. C works for d days. Total work: 20 + 3(d - 3) + 2d = 96 => 20 + 3d - 9 + 2d = 96 => 5d + 11 = 96 => 5d = 85 => d = 17 days.

   Topic: Quantitative Aptitude · hard

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SNAP Exam Subjects

Available practice subjects: General English, Quantitative Aptitude, Analytical & Logical Reasoning, Current Affairs. Select a subject for focused preparation. Coverage is not a guarantee of the complete official syllabus.

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