UCEED Practice Test 2026

About the UCEED exam

The Undergraduate Common Entrance Examination for Design (UCEED) is a design examination administered in India. It is designed to assess candidates' knowledge and proficiency across 4 key subject areas including Visualization & Spatial Ability, Observation & Design Sensitivity, Analytical & Logical Reasoning, Environmental & Social Awareness. This exam is widely recognized as an essential benchmark for students and professionals.

Use short UCEED practice sets to identify topics to revisit. Choose a subject and difficulty, answer questions, then review the explanations. New accounts get 30 question credits; further new questions use paid credits. Retaking previously seen questions is free.

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8 free UCEED practice questions (2026)

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1. A right triangular prism has a triangular base with sides of length 3, 4, and 5 units, and a length of 10 units. It initially rests on its largest rectangular face on a flat table. The prism is tipped over its 10-unit edge to the right so it rests on its second-largest rectangular face, and then tipped forward over its 10-unit edge so it rests on its smallest rectangular face. Finally, it is rotated 90 degrees counter-clockwise about its vertical axis when viewed from above. What is the height of the highest point of the prism from the table in this final position?

   • 2.4 units
   • 3.0 units
   • 4.0 units
   • 5.0 units
   Show answer & explanation

   Answer: C. 4.0 units

   Initially, the prism rests on its largest rectangular face (5x10), so its height is the altitude to the hypotenuse of the 3-4-5 triangle, which is (3*4)/5 = 2.4. Tipping it onto its second-largest face (4x10) makes its height the other leg, which is 3. Tipping it onto its smallest face (3x10) makes its height the remaining leg, which is 4. Rotating the prism about the vertical axis does not change its height. Thus, the final height is 4 units.

   Topic: Visualization & Spatial Ability · hard

2. A square sheet of paper is folded in half horizontally from bottom to top, then in half vertically from right to left. Finally, it is folded along the diagonal of the resulting smaller square from the bottom-left corner to the top-right corner. A semi-circular cut is made along the folded diagonal edge, and a small square hole is punched through the folded-over corner (which was originally the center of the sheet and the top-left of the quadrant). When the sheet is completely unfolded, what is the arrangement of the cuts?

   • 4 circular holes along the diagonals of each quadrant, 1 square hole at the center of the sheet, and 4 square holes at the four corners of the sheet
   • 4 circular holes along the diagonals of each quadrant, 4 square holes near the center, and 1 square hole at the center of the sheet
   • 2 circular holes along the main diagonal, 1 square hole at the center, and 2 square holes at opposite corners
   • 8 circular holes along the diagonals of each quadrant, 2 square holes near the center, and 4 square holes at the corners
   Show answer & explanation

   Answer: A. 4 circular holes along the diagonals of each quadrant, 1 square hole at the center of the sheet, and 4 square holes at the four corners of the sheet

   The diagonal fold line exists in all four quadrants of the unfolded sheet, so a semi-circular cut on this fold unfolds into a full circle in each of the 4 quadrants. The corner containing the punch represents both the absolute center of the sheet and the four outer corners of the original sheet. Therefore, unfolding yields 1 square hole at the absolute center and 4 square holes at the outer corners of the sheet.

   Topic: Visualization & Spatial Ability · hard

3. A solid cube of side 6 cm is painted red on all its faces and then cut into 216 identical small cubes of side 1 cm. A plane then slices through this collection of small cubes diagonally, passing through three vertices of the large cube: the top-left-front, the top-right-back, and the bottom-left-back. How many of the 1 cm small cubes that have exactly two painted faces are intersected by this slicing plane?

   • 8
   • 10
   • 12
   • 14
   Show answer & explanation

   Answer: C. 12

   By setting up a 3D coordinate system [0,6]^3, the plane equation is X - Y - Z + 6 = 0. Cubes with exactly two painted faces lie along the 12 edges of the 6x6x6 cube (excluding the corner cubes). Testing the coordinate spans of the 4 inner cubes along each of the 12 edges against the plane intersection condition reveals that exactly 12 of these edge cubes are cut by the plane.

   Topic: Visualization & Spatial Ability · hard

4. A 3D structure is built using 1x1x1 unit cubes inside a 3x3x3 grid. The Front, Top, and Side views of the structure are represented by binary matrices (where 1 indicates the presence of a block projection and 0 indicates empty space): Front View (top row to bottom row): [[1, 1, 0], [1, 0, 1], [0, 1, 1]] Top View (top row to bottom row): [[1, 0, 1], [0, 1, 1], [1, 1, 0]] Side View from right (top row to bottom row): [[0, 1, 1], [1, 1, 0], [1, 0, 1]] What is the maximum number of unit cubes that can be present in this structure?

   • 6
   • 7
   • 8
   • 9
   Show answer & explanation

   Answer: C. 8

   The maximum number of cubes at any coordinate (i, j, k) is constrained by the minimum of the corresponding projection values: A[i][j][k] <= min(T[i][j], F[k][j], S[k][i]). Evaluating this cell-by-cell for all 27 positions yields exactly 8 valid positions: (1,1,2), (2,0,2), (2,1,2) for the top layer; (0,0,1), (0,2,1), (1,2,1) for the middle layer; and (0,2,0), (2,1,0) for the bottom layer.

   Topic: Visualization & Spatial Ability · hard

5. A point light source is located at coordinates (0, 0, 10). A solid opaque sphere of radius 2 units is centered at (0, 0, 5). The sphere casts a shadow onto a flat screen located at the plane Z = 0. What is the area of the shadow on the screen?

   • 16π square units
   • 25π/2 square units
   • 400π/21 square units
   • 80π/3 square units
   Show answer & explanation

   Answer: C. 400π/21 square units

   The light source, sphere center, and screen are aligned along the Z-axis. In cross-section, the tangent from the light source (0, 10) to the sphere of radius 2 at (0, 5) forms a right triangle where the sine of the half-angle θ of the cone of shadow is 2/5. Thus, cos(θ) = √21/5 and tan(θ) = 2/√21. The radius of the shadow circle on Z=0 is 10 * tan(θ) = 20/√21. The area of the shadow is π * r^2 = 400π/21.

   Topic: Visualization & Spatial Ability · hard

6. A truncated octahedron is an Archimedean solid with 14 faces (6 squares and 8 regular hexagons). If this solid is unfolded along its edges to form a single continuous flat net, how many boundary edges (the perimeter of the net) will the flat shape have?

   • 36
   • 42
   • 46
   • 48
   Show answer & explanation

   Answer: C. 46

   The individual faces of the truncated octahedron have a total of (6*4) + (8*6) = 72 edges. To keep 14 faces connected in a single flat net, we must make exactly F - 1 = 13 joins (internal edges of the net). Each join reduces the number of boundary edges by 2. Therefore, the number of boundary edges of the net is 72 - (2 * 13) = 46.

   Topic: Visualization & Spatial Ability · hard

7. While there are many vertex configurations whose interior angles sum to exactly 360°, only 8 of them can be extended to form a globally consistent semi-regular (Archimedean) tessellation of the plane. Which of the following vertex configurations is mathematically impossible to extend into a semi-regular tessellation?

   • 3.12.12
   • 4.8.8
   • 3.4.4.6
   • 3.3.4.3.4
   Show answer & explanation

   Answer: C. 3.4.4.6

   For 3.4.4.6, the angle sum is 60° + 90° + 90° + 120° = 360°. However, if we attempt to tile the plane, the arrangement requires every vertex of a regular hexagon to alternate between squares and triangles. This forces the hexagon to be surrounded by squares sharing all its edges, leaving no way for the triangles to be placed consistently at every vertex without overlapping or leaving gaps.

   Topic: Visualization & Spatial Ability · hard

8. An artist is sketching a monumental building using three-point perspective, with the camera looking dramatically upwards (a worm's-eye view). Which of the following statements is correct regarding the arrangement of the vanishing points and the horizon line?

   • The horizon line lies above the third vanishing point (vertical vanishing point).
   • The horizon line passes through the left and right vanishing points, and the third vanishing point lies above the horizon line.
   • The third vanishing point must lie exactly on the horizon line.
   • The horizon line passes through the left and right vanishing points, and the third vanishing point lies below the horizon line.
   Show answer & explanation

   Answer: B. The horizon line passes through the left and right vanishing points, and the third vanishing point lies above the horizon line.

   In three-point perspective, the horizon line contains the left and right vanishing points. When the viewer looks upwards (worm's-eye view), the parallel vertical lines of the structure converge towards a third vanishing point (zenith) located in the sky, which lies above the horizon line.

   Topic: Visualization & Spatial Ability · hard

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UCEED Exam Subjects

Available practice subjects: Visualization & Spatial Ability, Observation & Design Sensitivity, Analytical & Logical Reasoning, Environmental & Social Awareness. Select a subject for focused preparation. Coverage is not a guarantee of the complete official syllabus.

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